dam thats a question
Any math teachers out there... I need help with math word problem
I understand that this is not directly a fishing issue...I just know that there are a lot of fishermen that are teachers and hopeful someone can help us out.
We are trying to figure out a college math question for the past 3 days now. We do have the final answer...that was the easy part..about 5 minutes...but we need to put in into an equation for x to show the work...that is the HARD part....so confusing.
here is the math word problem
A coin collection contains nickles, dimes, and quarters. There are twice as many dimes as quarters and seven more nickels than dimes. The total value of all of the coins is $3.10. How many quarters are in the collection?
GOOD LUCK
Thank you in advance
Lynne Peterson
National Bass West
Oh and btw...we do have a Vail Lake event coming up on September 12, 2009. It is OPEN to the public with NO MEMBERSHIP REQUIRED. The first place is guaranteed to payout $5,000 and second place will payout 2 year memberships to Vail Lake a $3,400-$4,200 value. NO MATTER HOW MANY TEAMS FISH!!!!! Third place and down will payout 1-5 based on participation. This is a day event. If you are not a member of VAIL LAKE you can pre-fish the day prior for $50 if you are pre-signed.
OH and Guy is going to bbq for everyone....Thank you GUY!
See you there.
We are trying to figure out a college math question for the past 3 days now. We do have the final answer...that was the easy part..about 5 minutes...but we need to put in into an equation for x to show the work...that is the HARD part....so confusing.
here is the math word problem
A coin collection contains nickles, dimes, and quarters. There are twice as many dimes as quarters and seven more nickels than dimes. The total value of all of the coins is $3.10. How many quarters are in the collection?
GOOD LUCK
Thank you in advance
Lynne Peterson
National Bass West
Oh and btw...we do have a Vail Lake event coming up on September 12, 2009. It is OPEN to the public with NO MEMBERSHIP REQUIRED. The first place is guaranteed to payout $5,000 and second place will payout 2 year memberships to Vail Lake a $3,400-$4,200 value. NO MATTER HOW MANY TEAMS FISH!!!!! Third place and down will payout 1-5 based on participation. This is a day event. If you are not a member of VAIL LAKE you can pre-fish the day prior for $50 if you are pre-signed.
OH and Guy is going to bbq for everyone....Thank you GUY!
See you there.
1 - 20 of 30 Posts
(0.05 X 17) + (10 X 0.10) + (5x) = $3.10
X = 0.25
X = 0.25
X + XSquared + (7 + X squared)= 3.10
Thats the actual way that the problem reads. Its been a long time. But you are going to factor out the squares and get the square root of 3.10 then divide by the X's that are left and that should give you your answer. Man its been a long time. Look at your factoring out rules in the book. I'm close
Jkole did it but not sure how he got 17 without showing the work.
I would think that X = number of quarters.
Good luck!
Thats the actual way that the problem reads. Its been a long time. But you are going to factor out the squares and get the square root of 3.10 then divide by the X's that are left and that should give you your answer. Man its been a long time. Look at your factoring out rules in the book. I'm close
Jkole did it but not sure how he got 17 without showing the work.
I would think that X = number of quarters.
Good luck!
Just like a math teacher...lolX + XSquared + (7 + X squared)= 3.10
Thats the actual way that the problem reads. Its been a long time. But you are going to factor out the squares and get the square root of 3.10 then divide by the X's that are left and that should give you your answer. Man its been a long time. Look at your factoring out rules in the book. I'm close
Jkole did it but not sure how he got 17 without showing the work.
I would think that X = number of quarters.
Good luck!
I did it in my head, then went backwards
You are on the right track, that 7 throws me...
Quarter QUAN. X Dimes QUAN 2X Nickles 2X+7 Total
$0.25 1 $0.20 2 $0.45 9 $0.90
$1.00 4 $0.80 8 $0.75 15 $2.55
$1.25 5 $1.00 10 $0.85 17 $3.10
$1.50 6 $1.20 12 $0.95 19 $3.65
Spreadsheets are great. X + 2X + 2X+7 = $3.10...Not X squared but 2X. Twice as many dies as quarters. If you squared 4 that is 16 and so on.
$0.25 1 $0.20 2 $0.45 9 $0.90
$1.00 4 $0.80 8 $0.75 15 $2.55
$1.25 5 $1.00 10 $0.85 17 $3.10
$1.50 6 $1.20 12 $0.95 19 $3.65
Spreadsheets are great. X + 2X + 2X+7 = $3.10...Not X squared but 2X. Twice as many dies as quarters. If you squared 4 that is 16 and so on.
What jkole said.
D = 2Q OR Q = D/2 = .5D twice as many dimes as quarters
N = D + 7 seven more nickels than dimes
.25Q + .1D + .05N = 3.10 total value of all of the coins is $3.10
.25(.5D) + .1D + .05(D + 7) = 3.10
.125D + .1D +.05D +.35 = 3.10
.275D = 2.75
D = 10 Dimes
Q = 5 quarters
N = 17 Nickels
10*.1 + 5*.25 + 17*.05 = 3.10
D = 2Q OR Q = D/2 = .5D twice as many dimes as quarters
N = D + 7 seven more nickels than dimes
.25Q + .1D + .05N = 3.10 total value of all of the coins is $3.10
.25(.5D) + .1D + .05(D + 7) = 3.10
.125D + .1D +.05D +.35 = 3.10
.275D = 2.75
D = 10 Dimes
Q = 5 quarters
N = 17 Nickels
10*.1 + 5*.25 + 17*.05 = 3.10
My daughter just said THANK YOU...THANK YOU....THANK YOU!!!! Now she will be able to sleep tonight without thinking about nickels, dimes and quarters!
She just joked that maybe I should put her homework on the forum!!!
The equation that she ended with is
.25x + .10 (2x) + .o5 (2x + 7) = $3.10
You guys rock.
Lynne
She just joked that maybe I should put her homework on the forum!!!
The equation that she ended with is
.25x + .10 (2x) + .o5 (2x + 7) = $3.10
You guys rock.
Lynne
Quarter QUAN. X Dimes QUAN 2X Nickles 2X+7 Total
$0.25 1 $0.20 2 $0.45 9 $0.90
$1.00 4 $0.80 8 $0.75 15 $2.55
$1.25 5 $1.00 10 $0.85 17 $3.10
$1.50 6 $1.20 12 $0.95 19 $3.65
Spreadsheets are great. X + 2X + 2X+7 = $3.10
nevermind....I am slow....
Q = number of quarters
N = number of nickels
D = number of dimes
Working equation is
0.25Q + 0.05N + 0.10D = 3.10
N = D + 7
D = 2Q
Substituting appropriate relationships,
0.25Q + 0.05(D + 7) + (0.10) 2Q = 3.10
0.25Q + 0.05(2Q + 7) + 0.20Q = 3.10
0.25Q + 0.10Q + 0.35 + 0.20Q = 3.10
Combining terms,
0.55Q = 3.10 - 0.35
0.55Q = 2.75
Q = 5
CHECK:
D = 2Q = 2(5) = 10
N = D + 7 = 10 + 7 = 17
0.25(5) + 0.10(10) + 0.05(17) = 1.25 + 1.00 + 0.85 = 3.10
Hope this helps.
N = number of nickels
D = number of dimes
Working equation is
0.25Q + 0.05N + 0.10D = 3.10
N = D + 7
D = 2Q
Substituting appropriate relationships,
0.25Q + 0.05(D + 7) + (0.10) 2Q = 3.10
0.25Q + 0.05(2Q + 7) + 0.20Q = 3.10
0.25Q + 0.10Q + 0.35 + 0.20Q = 3.10
Combining terms,
0.55Q = 3.10 - 0.35
0.55Q = 2.75
Q = 5
CHECK:
D = 2Q = 2(5) = 10
N = D + 7 = 10 + 7 = 17
0.25(5) + 0.10(10) + 0.05(17) = 1.25 + 1.00 + 0.85 = 3.10
Hope this helps.
Holy Crap. And all I thought I needed to know was that 5 made a limit and if they were big enough I won.................You guys totally rock thats all I can say about that..........
I still can't figure out if I'm holding a 3 pound bass or a 9'er. I always round up! :biggrin:Holy Crap. And all I thought I needed to know was that 5 made a limit and if they were big enough I won.................You guys totally rock thats all I can say about that..........
screw this, I'm going fishin.....
Damn dave. Thought my eyes were going bad there for a second!
I wanted to help you but I ran out of fingers and toes.
THAT IS RIGHT I SCREWED UP AND SQUARED THEM. THAT WILL MAKE IT EVEN EASIER TO COMPLETE. THAT WAS FUN.
That is half the fun, remembering how do apply those lessons. The 4 rules of algebra. We can have Del put a new forum on here, math brain teasers. My nephew was in the 8th grade and all last year I was pounding out some very strange problems.THAT IS RIGHT I SCREWED UP AND SQUARED THEM. THAT WILL MAKE IT EVEN EASIER TO COMPLETE. THAT WAS FUN.
X = How do I post about our open TMX to thousands of people & not look like a spammer. JMHO (it was cool how the zone had the answer to the math question).
Rock On! Did I pass this class or fail?
Rock On! Did I pass this class or fail?
1 - 20 of 30 Posts
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